10s^2-19s+7=0

Solution for 10s^2-19s+7=0 equation:

10s^2-19s+7=0

a = 10; b = -19; c = +7;
Δ = b2-4ac
Δ = -192-4·10·7
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-9}{2*10}=\frac{10}{20}
=1/2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+9}{2*10}=\frac{28}{20}
=1+2/5
$